 | Sample Lab Questions Investigation #10:
"Copper(II) and Algae"
|
These questions have been taken from lab quizzes given in previous years.
Some of the answers are listed at the end.
Note: The subscripts and superscripts may not appear as such. It depends upon your web browser.
- 1.
- (1pt) Was the copper(II) ion more easily detected in a pure water solution or a solution of ammonia? How could you tell?
- 2.
- (2pts) Explain briefly how you determined the density of your algaecide solution.
- 3.
- (2pts) Define the following units of concentration:
- (a) molarity (M)
- (b) parts per million (ppm)
- 4.
- a. (1pt) Sketch what is meant by the bottom of the meniscus in a buret.
- b. (1pt) To how many decimal places should you read a buret?
- 5.
- (1pt) The diet of any living organism must contain not only the proper elements, but also the proper range of their concentrations. Why?
- 6.
- a. (1pt) Describe the process of dilution.
- b. (3pts) Calculate the volume of 6.00 x 10-3 M CuSO4
5H2O solution required to prepare 100.0 mL of 4.50 x 10-4 M CuSO4
5H2O solution.
- 7.
- (2pts) Calculate the mass of CuSO4
5H2O required for the preparation of 100.0 mL of 6.00 x 10-3 M solution.
- 8.
- a. (3pts) Calculate the number of milligrams of Cu2+ in 1.00 L of solution of 4.50 x 10-4 M CuSO4
5H2O.
- b. (3pts) Assuming a solution density of 1.01 g/mL, what is the concentration of Cu2+ (in ppm) of this solution?
- 9.
- (3pts) A student prepared 3 aqueous solutions of CuSO4 according to the following procedures. Calculate the moarities of CuSO4 for solutions I, II, and III.
- Solution I: 0.4344 g of CuSO4
5H2O was dissolved and diluted to 100.0 mL
- Solution II: 8.28 mL of Solution I was diluted to 100.0 mL
- Solution III: 38.20 mL of Solution II was diluted to 100.0 mL.
Answers
6. | b. | 7.50 mL solution |
7. | | 0.150 g |
8. | a. | 28.6 mg |
| b. | 28.3 ppm |
9. | | Solution I: 0.01740 M CuSO4 |
| | Solution II: 0.001441 M CuSO4 |
| | Solution III: 5.505 x 10-4 M CuSO4 |

To report any corrections, please e-mail Dr. Wendy Keeney-Kennicutt.